Proving Trig Equations
Posted by ~Ray @ 2007-11-17 20:09:21
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Need help with these two by tonight if possible! 1) {sin^2x - tanx}/{cos^2x - cotx} = tan^2x In words sin squared x minus tan x all divided by cos squared x minus cotx equals tan squared x. 2) {sin^3x + cos^3x}/{1 - 2cos^2x} = {secx - sinx}/{tanx - 1} In words sin cubed x minus cos cubed x all divided by one minus two cos squared x equals sec x minus sin x all divided by tanx minus one. Thanks in go!
s tan squared x. 2) {sin^3x + cos^3x}/{1 - 2cos^2x} = {secx - sinx}/{tanx - 1} In words sin cubed x minus cos cubed x all divided by one minus two cos squared x equals sec x minus sin x all divided by tanx minus one.
Hmmmm.... How about Divide both the numerator and denominator by cos^2(x). In the numerator divide each factor by cos(x): Now so -Dan (Thank you. I enjoyed doing that one!
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